# MLB Beat the Streak In A Day

• 09-27-2012, 11:06 AM
WildcatFan
MLB Beat the Streak In A Day
How about this? MLB is offering \$5.6 million to anyone who can pick 57 players who will get a hit in tomorrow's games. It's got to be impossible, but of course I'm giving it a shot. Care to make it a Redszone challenge? Pride at stake.

http://mlb.mlb.com/mlb/fantasy/btsday/index.jsp

[Edit: 57 players. You have to beat the streak, not tie.]
• 09-27-2012, 11:50 AM
RedsMan3203
Re: MLB Beat the Streak In A Day
I'm in it.... This should be fun...
• 09-27-2012, 12:44 PM
AtomicDumpling
Re: MLB Beat the Streak In A Day
I am in.
• 09-27-2012, 02:14 PM
RedsManRick
Re: MLB Beat the Streak In A Day
Let's say you have 56 batters who each are .300 hitters who will get 4 PA and don't walk at all. The chances of all 56 getting a hit is: ((1-(.7^4)^56 or 1 in 4,760,352. Good luck!

Good to know you can get it out of the way all at once, but good luck!
• 09-27-2012, 02:28 PM
medford
Re: MLB Beat the Streak In A Day
Quote:

Originally Posted by RedsManRick
Let's say you have 56 batters who each are .300 hitters who will get 4 PA and don't walk at all. The chances of all 56 getting a hit is: ((1-(.7^4)^56 or 1 in 4,760,352. Good luck!

Good to know you can get it out of the way all at once, but good luck!

So you're saying I have a chance?!
• 09-27-2012, 02:42 PM
AtomicDumpling
Re: MLB Beat the Streak In A Day
Just the odds that all 57 of your players even play that day are slim to none. But I took the challenge!
• 09-27-2012, 02:56 PM
WrongVerb
Re: MLB Beat the Streak In A Day
Quote:

Originally Posted by RedsManRick
Let's say you have 56 batters who each are .300 hitters who will get 4 PA and don't walk at all. The chances of all 56 getting a hit is: ((1-(.7^4)^56 or 1 in 4,760,352. Good luck!

Good to know you can get it out of the way all at once, but good luck!

Considering there is a prize involved, getting infinite odds (no entry fee) is a damn good deal.
• 09-27-2012, 03:12 PM
WildcatFan
Re: MLB Beat the Streak In A Day
Quote:

Originally Posted by RedsManRick
Let's say you have 56 batters who each are .300 hitters who will get 4 PA and don't walk at all. The chances of all 56 getting a hit is: ((1-(.7^4)^56 or 1 in 4,760,352. Good luck!

Good to know you can get it out of the way all at once, but good luck!

That's why I put it here. Just to show that I'm the best RZer at calling shots!
• 09-27-2012, 03:16 PM
Captain Hook
Re: MLB Beat the Streak In A Day
I really want to win this thing!:D
• 09-27-2012, 04:56 PM
FlightRick
Re: MLB Beat the Streak In A Day
1 in 4.7 million sounds daunting.

I choose to look at it this way: I just have to accurately pick 4 players in a game who will get a hit. Easy as pie.

And then I have to do it 14 more times. D'oh.
• 09-27-2012, 09:15 PM
RedFanAlways1966
Re: MLB Beat the Streak In A Day
Not trying, b/c I'll get screwed. I'll probably get 56 guys with a hit. Then #57 will come to the plate hitless in the 9th inning. He will get an obvious infield hit, but... the official scorer will be related to the Cubs official scorer who used to rule all of Ryne Sandberg's errors as hits. He'll try to make up for his relative's injustice by giving the infielder an error to make it OK.
• 09-28-2012, 06:33 PM
PickOff
Re: MLB Beat the Streak In A Day
Quote:

Originally Posted by AtomicDumpling
Just the odds that all 57 of your players even play that day are slim to none. But I took the challenge!

Well,all the lineups are out now except the Pads, Giants, and A's. Good luck all!
• 09-28-2012, 10:10 PM
marcshoe
Re: MLB Beat the Streak In A Day
I picked at least one player on every team except one. The Pirates. I joked that Homer was going to no hit them.
• 09-28-2012, 11:57 PM
RedsMan3203
Re: MLB Beat the Streak In A Day
So far, I've gotten 18 correct.... 11 inncorect :)